% Functions
Every Rust program has at least one function, the main
function:
fn main() {
}
This is the simplest possible function declaration. As we mentioned before,
fn
says ‘this is a function’, followed by the name, some parentheses because
this function takes no arguments, and then some curly braces to indicate the
body. Here’s a function named foo
:
fn foo() {
}
So, what about taking arguments? Here’s a function that prints a number:
fn print_number(x: i32) {
println!("x is: {}", x);
}
Here’s a complete program that uses print_number
:
fn main() {
print_number(5);
}
fn print_number(x: i32) {
println!("x is: {}", x);
}
As you can see, function arguments work very similar to let
declarations:
you add a type to the argument name, after a colon.
Here’s a complete program that adds two numbers together and prints them:
fn main() {
print_sum(5, 6);
}
fn print_sum(x: i32, y: i32) {
println!("sum is: {}", x + y);
}
You separate arguments with a comma, both when you call the function, as well as when you declare it.
Unlike let
, you must declare the types of function arguments. This does
not work:
fn print_sum(x, y) {
println!("sum is: {}", x + y);
}
You get this error:
expected one of `!`, `:`, or `@`, found `)`
fn print_sum(x, y) {
This is a deliberate design decision. While full-program inference is possible, languages which have it, like Haskell, often suggest that documenting your types explicitly is a best-practice. We agree that forcing functions to declare types while allowing for inference inside of function bodies is a wonderful sweet spot between full inference and no inference.
What about returning a value? Here’s a function that adds one to an integer:
fn add_one(x: i32) -> i32 {
x + 1
}
Rust functions return exactly one value, and you declare the type after an
‘arrow’, which is a dash (-
) followed by a greater-than sign (>
). The last
line of a function determines what it returns. You’ll note the lack of a
semicolon here. If we added it in:
fn add_one(x: i32) -> i32 {
x + 1;
}
We would get an error:
error: not all control paths return a value
fn add_one(x: i32) -> i32 {
x + 1;
}
help: consider removing this semicolon:
x + 1;
^
This reveals two interesting things about Rust: it is an expression-based language, and semicolons are different from semicolons in other ‘curly brace and semicolon’-based languages. These two things are related.
Expressions vs. Statements
Rust is primarily an expression-based language. There are only two kinds of statements, and everything else is an expression.
So what's the difference? Expressions return a value, and statements do not.
That’s why we end up with ‘not all control paths return a value’ here: the
statement x + 1;
doesn’t return a value. There are two kinds of statements in
Rust: ‘declaration statements’ and ‘expression statements’. Everything else is
an expression. Let’s talk about declaration statements first.
In some languages, variable bindings can be written as expressions, not statements. Like Ruby:
x = y = 5
In Rust, however, using let
to introduce a binding is not an expression. The
following will produce a compile-time error:
let x = (let y = 5); // Expected identifier, found keyword `let`.
The compiler is telling us here that it was expecting to see the beginning of
an expression, and a let
can only begin a statement, not an expression.
Note that assigning to an already-bound variable (e.g. y = 5
) is still an
expression, although its value is not particularly useful. Unlike other
languages where an assignment evaluates to the assigned value (e.g. 5
in the
previous example), in Rust the value of an assignment is an empty tuple ()
because the assigned value can have only one owner, and any
other returned value would be too surprising:
let mut y = 5;
let x = (y = 6); // `x` has the value `()`, not `6`.
The second kind of statement in Rust is the expression statement. Its purpose is to turn any expression into a statement. In practical terms, Rust's grammar expects statements to follow other statements. This means that you use semicolons to separate expressions from each other. This means that Rust looks a lot like most other languages that require you to use semicolons at the end of every line, and you will see semicolons at the end of almost every line of Rust code you see.
What is this exception that makes us say "almost"? You saw it already, in this code:
fn add_one(x: i32) -> i32 {
x + 1
}
Our function claims to return an i32
, but with a semicolon, it would return
()
instead. Rust realizes this probably isn’t what we want, and suggests
removing the semicolon in the error we saw before.
Early returns
But what about early returns? Rust does have a keyword for that, return
:
fn foo(x: i32) -> i32 {
return x;
// We never run this code!
x + 1
}
Using a return
as the last line of a function works, but is considered poor
style:
fn foo(x: i32) -> i32 {
return x + 1;
}
The previous definition without return
may look a bit strange if you haven’t
worked in an expression-based language before, but it becomes intuitive over
time.
Diverging functions
Rust has some special syntax for ‘diverging functions’, which are functions that do not return:
fn diverges() -> ! {
panic!("This function never returns!");
}
panic!
is a macro, similar to println!()
that we’ve already seen. Unlike
println!()
, panic!()
causes the current thread of execution to crash with
the given message. Because this function will cause a crash, it will never
return, and so it has the type ‘!
’, which is read ‘diverges’.
If you add a main function that calls diverges()
and run it, you’ll get
some output that looks like this:
thread ‘main’ panicked at ‘This function never returns!’, hello.rs:2
If you want more information, you can get a backtrace by setting the
RUST_BACKTRACE
environment variable:
$ RUST_BACKTRACE=1 ./diverges
thread 'main' panicked at 'This function never returns!', hello.rs:2
stack backtrace:
1: 0x7f402773a829 - sys::backtrace::write::h0942de78b6c02817K8r
2: 0x7f402773d7fc - panicking::on_panic::h3f23f9d0b5f4c91bu9w
3: 0x7f402773960e - rt::unwind::begin_unwind_inner::h2844b8c5e81e79558Bw
4: 0x7f4027738893 - rt::unwind::begin_unwind::h4375279447423903650
5: 0x7f4027738809 - diverges::h2266b4c4b850236beaa
6: 0x7f40277389e5 - main::h19bb1149c2f00ecfBaa
7: 0x7f402773f514 - rt::unwind::try::try_fn::h13186883479104382231
8: 0x7f402773d1d8 - __rust_try
9: 0x7f402773f201 - rt::lang_start::ha172a3ce74bb453aK5w
10: 0x7f4027738a19 - main
11: 0x7f402694ab44 - __libc_start_main
12: 0x7f40277386c8 - <unknown>
13: 0x0 - <unknown>
If you need to override an already set RUST_BACKTRACE
,
in cases when you cannot just unset the variable,
then set it to 0
to avoid getting a backtrace.
Any other value (even no value at all) turns on backtrace.
$ export RUST_BACKTRACE=1
...
$ RUST_BACKTRACE=0 ./diverges
thread 'main' panicked at 'This function never returns!', hello.rs:2
note: Run with `RUST_BACKTRACE=1` for a backtrace.
RUST_BACKTRACE
also works with Cargo’s run
command:
$ RUST_BACKTRACE=1 cargo run
Running `target/debug/diverges`
thread 'main' panicked at 'This function never returns!', hello.rs:2
stack backtrace:
1: 0x7f402773a829 - sys::backtrace::write::h0942de78b6c02817K8r
2: 0x7f402773d7fc - panicking::on_panic::h3f23f9d0b5f4c91bu9w
3: 0x7f402773960e - rt::unwind::begin_unwind_inner::h2844b8c5e81e79558Bw
4: 0x7f4027738893 - rt::unwind::begin_unwind::h4375279447423903650
5: 0x7f4027738809 - diverges::h2266b4c4b850236beaa
6: 0x7f40277389e5 - main::h19bb1149c2f00ecfBaa
7: 0x7f402773f514 - rt::unwind::try::try_fn::h13186883479104382231
8: 0x7f402773d1d8 - __rust_try
9: 0x7f402773f201 - rt::lang_start::ha172a3ce74bb453aK5w
10: 0x7f4027738a19 - main
11: 0x7f402694ab44 - __libc_start_main
12: 0x7f40277386c8 - <unknown>
13: 0x0 - <unknown>
A diverging function can be used as any type:
# fn diverges() -> ! {
# panic!("This function never returns!");
# }
let x: i32 = diverges();
let x: String = diverges();
Function pointers
We can also create variable bindings which point to functions:
let f: fn(i32) -> i32;
f
is a variable binding which points to a function that takes an i32
as
an argument and returns an i32
. For example:
fn plus_one(i: i32) -> i32 {
i + 1
}
// Without type inference:
let f: fn(i32) -> i32 = plus_one;
// With type inference:
let f = plus_one;
We can then use f
to call the function:
# fn plus_one(i: i32) -> i32 { i + 1 }
# let f = plus_one;
let six = f(5);